Base | Representation |
---|---|
bin | 111111000011101011… |
… | …1110011111011101001 |
3 | 110221112022111111011101 |
4 | 1332013113303323221 |
5 | 4204312234333421 |
6 | 142113040401401 |
7 | 12532466542366 |
oct | 1760727637351 |
9 | 427468444141 |
10 | 135415152361 |
11 | 5247a361265 |
12 | 222b2316261 |
13 | ca00a4b7b8 |
14 | 67a875746d |
15 | 37c8473191 |
hex | 1f875f3ee9 |
135415152361 has 2 divisors, whose sum is σ = 135415152362. Its totient is φ = 135415152360.
The previous prime is 135415152329. The next prime is 135415152407. The reversal of 135415152361 is 163251514531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105020716761 + 30394435600 = 324069^2 + 174340^2 .
It is a cyclic number.
It is not a de Polignac number, because 135415152361 - 25 = 135415152329 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135415152361.
It is not a weakly prime, because it can be changed into another prime (135415152311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67707576180 + 67707576181.
It is an arithmetic number, because the mean of its divisors is an integer number (67707576181).
Almost surely, 2135415152361 is an apocalyptic number.
It is an amenable number.
135415152361 is a deficient number, since it is larger than the sum of its proper divisors (1).
135415152361 is an equidigital number, since it uses as much as digits as its factorization.
135415152361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 37.
Adding to 135415152361 its reverse (163251514531), we get a palindrome (298666666892).
The spelling of 135415152361 in words is "one hundred thirty-five billion, four hundred fifteen million, one hundred fifty-two thousand, three hundred sixty-one".
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