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1354213401377 is a prime number
BaseRepresentation
bin10011101101001101011…
…010001010001100100001
311210110110110102120221212
4103231031122022030201
5134141412112321002
62514041140555505
7166560445662224
oct23551532121441
94713413376855
101354213401377
11482356185041
1219a5573b2b95
139a917a55975
14497896dd5bb
152535d645352
hex13b4d68a321

1354213401377 has 2 divisors, whose sum is σ = 1354213401378. Its totient is φ = 1354213401376.

The previous prime is 1354213401347. The next prime is 1354213401461. The reversal of 1354213401377 is 7731043124531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 681019407121 + 673193994256 = 825239^2 + 820484^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354213401377 - 26 = 1354213401313 is a prime.

It is a super-2 number, since 2×13542134013772 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1354213401347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677106700688 + 677106700689.

It is an arithmetic number, because the mean of its divisors is an integer number (677106700689).

Almost surely, 21354213401377 is an apocalyptic number.

It is an amenable number.

1354213401377 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354213401377 is an equidigital number, since it uses as much as digits as its factorization.

1354213401377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 211680, while the sum is 41.

The spelling of 1354213401377 in words is "one trillion, three hundred fifty-four billion, two hundred thirteen million, four hundred one thousand, three hundred seventy-seven".