1354213401403 has 4 divisors (see below), whose sum is σ = 1354419497368. Its totient is φ = 1354007305440.

The previous prime is 1354213401377. The next prime is 1354213401461. The reversal of 1354213401403 is 3041043124531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1354213401403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1354213401493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103038126 + ... + 103051267.

It is an arithmetic number, because the mean of its divisors is an integer number (338604874342).

Almost surely, 2^{1354213401403} is an apocalyptic number.

1354213401403 is a deficient number, since it is larger than the sum of its proper divisors (206095965).

1354213401403 is an equidigital number, since it uses as much as digits as its factorization.

1354213401403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 206095964.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1354213401403 its reverse (3041043124531), we get a palindrome (4395256525934).

The spelling of 1354213401403 in words is "one trillion, three hundred fifty-four billion, two hundred thirteen million, four hundred one thousand, four hundred three".