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1354213401493 is a prime number
BaseRepresentation
bin10011101101001101011…
…010001010001110010101
311210110110110102121010011
4103231031122022032111
5134141412112321433
62514041141000221
7166560445662451
oct23551532121625
94713413377104
101354213401493
11482356185137
1219a5573b3071
139a917a55a34
14497896dd661
152535d6453cd
hex13b4d68a395

1354213401493 has 2 divisors, whose sum is σ = 1354213401494. Its totient is φ = 1354213401492.

The previous prime is 1354213401487. The next prime is 1354213401521. The reversal of 1354213401493 is 3941043124531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1333244334244 + 20969067249 = 1154662^2 + 144807^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354213401493 - 25 = 1354213401461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354213401293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677106700746 + 677106700747.

It is an arithmetic number, because the mean of its divisors is an integer number (677106700747).

Almost surely, 21354213401493 is an apocalyptic number.

It is an amenable number.

1354213401493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354213401493 is an equidigital number, since it uses as much as digits as its factorization.

1354213401493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 40.

The spelling of 1354213401493 in words is "one trillion, three hundred fifty-four billion, two hundred thirteen million, four hundred one thousand, four hundred ninety-three".