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135421423537 is a prime number
BaseRepresentation
bin111111000011110111…
…1101110111110110001
3110221112202022002121011
41332013233232332301
54204320341023122
6142113423030521
712532604051611
oct1760757567661
9427482262534
10135421423537
1152482954954
12222b443b441
13ca0213605a
1467a950aa41
1537c8cb1377
hex1f87beefb1

135421423537 has 2 divisors, whose sum is σ = 135421423538. Its totient is φ = 135421423536.

The previous prime is 135421423531. The next prime is 135421423573. The reversal of 135421423537 is 735324124531.

Together with next prime (135421423573) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129510735376 + 5910688161 = 359876^2 + 76881^2 .

It is an emirp because it is prime and its reverse (735324124531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135421423537 - 223 = 135413034929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135421423537.

It is not a weakly prime, because it can be changed into another prime (135421423531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710711768 + 67710711769.

It is an arithmetic number, because the mean of its divisors is an integer number (67710711769).

Almost surely, 2135421423537 is an apocalyptic number.

It is an amenable number.

135421423537 is a deficient number, since it is larger than the sum of its proper divisors (1).

135421423537 is an equidigital number, since it uses as much as digits as its factorization.

135421423537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 302400, while the sum is 40.

The spelling of 135421423537 in words is "one hundred thirty-five billion, four hundred twenty-one million, four hundred twenty-three thousand, five hundred thirty-seven".