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135421543111433 is a prime number
BaseRepresentation
bin11110110010101001001000…
…111110001101101100001001
3122202111011200011212020100212
4132302221020332031230021
5120222221310014031213
61200003444214210505
740344612036613655
oct3662511076155411
9582434604766325
10135421543111433
113a170a54721607
1213231728953a35
135a7427326a4a7
14256261ad15a65
15109c959b429a8
hex7b2a48f8db09

135421543111433 has 2 divisors, whose sum is σ = 135421543111434. Its totient is φ = 135421543111432.

The previous prime is 135421543111409. The next prime is 135421543111447. The reversal of 135421543111433 is 334111345124531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97423848603904 + 37997694507529 = 9870352^2 + 6164227^2 .

It is a cyclic number.

It is not a de Polignac number, because 135421543111433 - 214 = 135421543095049 is a prime.

It is a super-2 number, since 2×1354215431114332 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (135421543111403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710771555716 + 67710771555717.

It is an arithmetic number, because the mean of its divisors is an integer number (67710771555717).

Almost surely, 2135421543111433 is an apocalyptic number.

It is an amenable number.

135421543111433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135421543111433 is an equidigital number, since it uses as much as digits as its factorization.

135421543111433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 259200, while the sum is 41.

Adding to 135421543111433 its reverse (334111345124531), we get a palindrome (469532888235964).

The spelling of 135421543111433 in words is "one hundred thirty-five trillion, four hundred twenty-one billion, five hundred forty-three million, one hundred eleven thousand, four hundred thirty-three".