Base | Representation |
---|---|
bin | 10011101101001101111… |
… | …100101011011010100111 |
3 | 11210110111002110022210202 |
4 | 103231031330223122213 |
5 | 134141421421402333 |
6 | 2514042102541115 |
7 | 166560615621110 |
oct | 23551574533247 |
9 | 4713432408722 |
10 | 1354222450343 |
11 | 4823602a5724 |
12 | 19a55a43779b |
13 | 9a9198a3699 |
14 | 4978a9b7207 |
15 | 2535e3315e8 |
hex | 13b4df2b6a7 |
1354222450343 has 8 divisors (see below), whose sum is σ = 1547703306240. Its totient is φ = 1160746720920.
The previous prime is 1354222450337. The next prime is 1354222450403. The reversal of 1354222450343 is 3430542224531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1354222450343 - 218 = 1354222188199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1354222450297 and 1354222450306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1354222450643) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 697823 + ... + 1787568.
It is an arithmetic number, because the mean of its divisors is an integer number (193462913280).
Almost surely, 21354222450343 is an apocalyptic number.
1354222450343 is a deficient number, since it is larger than the sum of its proper divisors (193480855897).
1354222450343 is an equidigital number, since it uses as much as digits as its factorization.
1354222450343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2563237.
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 1354222450343 its reverse (3430542224531), we get a palindrome (4784764674874).
The spelling of 1354222450343 in words is "one trillion, three hundred fifty-four billion, two hundred twenty-two million, four hundred fifty thousand, three hundred forty-three".
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