Base | Representation |
---|---|
bin | 11110110010101001111101… |
… | …110111001001101001101111 |
3 | 122202111020222000112211020201 |
4 | 132302221331313021221233 |
5 | 120222230114143433320 |
6 | 1200004112233054331 |
7 | 40344643033106455 |
oct | 3662517567115157 |
9 | 582436860484221 |
10 | 135422430452335 |
11 | 3a17136a5979a4 |
12 | 13231935b573a7 |
13 | 5a74385050b90 |
14 | 25626a2ad89d5 |
15 | 109c9ac9bd70a |
hex | 7b2a7ddc9a6f |
135422430452335 has 64 divisors (see below), whose sum is σ = 183606793493760. Its totient is φ = 95188262400000.
The previous prime is 135422430452303. The next prime is 135422430452363. The reversal of 135422430452335 is 533254034224531.
It is not a de Polignac number, because 135422430452335 - 25 = 135422430452303 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2061159985 + ... + 2061225685.
It is an arithmetic number, because the mean of its divisors is an integer number (2868856148340).
Almost surely, 2135422430452335 is an apocalyptic number.
135422430452335 is a deficient number, since it is larger than the sum of its proper divisors (48184363041425).
135422430452335 is a wasteful number, since it uses less digits than its factorization.
135422430452335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81220.
The product of its (nonzero) digits is 5184000, while the sum is 46.
Adding to 135422430452335 its reverse (533254034224531), we get a palindrome (668676464676866).
The spelling of 135422430452335 in words is "one hundred thirty-five trillion, four hundred twenty-two billion, four hundred thirty million, four hundred fifty-two thousand, three hundred thirty-five".
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