Base | Representation |
---|---|
bin | 11110110010101010000010… |
… | …101100011001111001111100 |
3 | 122202111021011200002120002211 |
4 | 132302222002230121321330 |
5 | 120222230300422141104 |
6 | 1200004124250430204 |
7 | 40344645036144442 |
oct | 3662520254317174 |
9 | 582437150076084 |
10 | 135422511521404 |
11 | 3a171401329328 |
12 | 13231959132364 |
13 | 5a74398a96a43 |
14 | 25626ad79cb92 |
15 | 109c9b4b83e04 |
hex | 7b2a82b19e7c |
135422511521404 has 12 divisors (see below), whose sum is σ = 236989518217704. Its totient is φ = 67711220602064.
The previous prime is 135422511521393. The next prime is 135422511521411. The reversal of 135422511521404 is 404125115224531.
135422511521404 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117554 + ... + 16495270.
It is an arithmetic number, because the mean of its divisors is an integer number (19749126518142).
Almost surely, 2135422511521404 is an apocalyptic number.
It is an amenable number.
135422511521404 is a deficient number, since it is larger than the sum of its proper divisors (101567006696300).
135422511521404 is a wasteful number, since it uses less digits than its factorization.
135422511521404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17579324 (or 17579322 counting only the distinct ones).
The product of its (nonzero) digits is 192000, while the sum is 40.
Adding to 135422511521404 its reverse (404125115224531), we get a palindrome (539547626745935).
The spelling of 135422511521404 in words is "one hundred thirty-five trillion, four hundred twenty-two billion, five hundred eleven million, five hundred twenty-one thousand, four hundred four".
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