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13542253334 = 27399162553
BaseRepresentation
bin11001001110010111…
…00110001100010110
31021221210010202012022
430213023212030112
5210213304101314
610115441253142
7656406153101
oct144713461426
937853122168
1013542253334
11581a281405
12275b3341b2
13137a82c16c
1492679d738
15543d6478e
hex3272e6316

13542253334 has 8 divisors (see below), whose sum is σ = 20340869880. Its totient is φ = 6761963376.

The previous prime is 13542253331. The next prime is 13542253343. The reversal of 13542253334 is 43335224531.

13542253334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13542253294 and 13542253303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13542253331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4579799 + ... + 4582754.

It is an arithmetic number, because the mean of its divisors is an integer number (2542608735).

Almost surely, 213542253334 is an apocalyptic number.

13542253334 is a deficient number, since it is larger than the sum of its proper divisors (6798616546).

13542253334 is an equidigital number, since it uses as much as digits as its factorization.

13542253334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9163294.

The product of its digits is 129600, while the sum is 35.

Adding to 13542253334 its reverse (43335224531), we get a palindrome (56877477865).

The spelling of 13542253334 in words is "thirteen billion, five hundred forty-two million, two hundred fifty-three thousand, three hundred thirty-four".

Divisors: 1 2 739 1478 9162553 18325106 6771126667 13542253334