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13542513403 is a prime number
BaseRepresentation
bin11001001110011001…
…00101101011111011
31021221210121221221111
430213030211223323
5210213340412103
610115451021151
7656411315236
oct144714455373
937853557844
1013542513403
11581a439841
12275b43a7b7
13137a8c0653
1492682a41d
15543db686d
hex327325afb

13542513403 has 2 divisors, whose sum is σ = 13542513404. Its totient is φ = 13542513402.

The previous prime is 13542513389. The next prime is 13542513419. The reversal of 13542513403 is 30431524531.

It is a weak prime.

It is an emirp because it is prime and its reverse (30431524531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13542513403 - 25 = 13542513371 is a prime.

It is not a weakly prime, because it can be changed into another prime (13542513433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771256701 + 6771256702.

It is an arithmetic number, because the mean of its divisors is an integer number (6771256702).

Almost surely, 213542513403 is an apocalyptic number.

13542513403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13542513403 is an equidigital number, since it uses as much as digits as its factorization.

13542513403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 13542513403 in words is "thirteen billion, five hundred forty-two million, five hundred thirteen thousand, four hundred three".