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1354253665013 = 2358880594131
BaseRepresentation
bin10011101101001111110…
…011110000001011110101
311210110120021012012021122
4103231033303300023311
5134142002414240023
62514045135553325
7166561445136014
oct23551763601365
94713507165248
101354253665013
11482376985777
1219a56898b845
139a9231b24c2
1449790bc0a7b
1525361e4a2c8
hex13b4fcf02f5

1354253665013 has 4 divisors (see below), whose sum is σ = 1413134259168. Its totient is φ = 1295373070860.

The previous prime is 1354253664983. The next prime is 1354253665057. The reversal of 1354253665013 is 3105663524531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1354253665013 - 26 = 1354253664949 is a prime.

It is a super-2 number, since 2×13542536650132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1354253665073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29440297043 + ... + 29440297088.

It is an arithmetic number, because the mean of its divisors is an integer number (353283564792).

Almost surely, 21354253665013 is an apocalyptic number.

It is an amenable number.

1354253665013 is a deficient number, since it is larger than the sum of its proper divisors (58880594155).

1354253665013 is an equidigital number, since it uses as much as digits as its factorization.

1354253665013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58880594154.

The product of its (nonzero) digits is 972000, while the sum is 44.

The spelling of 1354253665013 in words is "one trillion, three hundred fifty-four billion, two hundred fifty-three million, six hundred sixty-five thousand, thirteen".

Divisors: 1 23 58880594131 1354253665013