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1354253665057 is a prime number
BaseRepresentation
bin10011101101001111110…
…011110000001100100001
311210110120021012012100021
4103231033303300030201
5134142002414240212
62514045135553441
7166561445136106
oct23551763601441
94713507165307
101354253665057
11482376985807
1219a56898b881
139a9231b2527
1449790bc0aad
1525361e4a307
hex13b4fcf0321

1354253665057 has 2 divisors, whose sum is σ = 1354253665058. Its totient is φ = 1354253665056.

The previous prime is 1354253664983. The next prime is 1354253665067. The reversal of 1354253665057 is 7505663524531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1107116422416 + 247137242641 = 1052196^2 + 497129^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354253665057 - 215 = 1354253632289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1354253664995 and 1354253665013.

It is not a weakly prime, because it can be changed into another prime (1354253665067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677126832528 + 677126832529.

It is an arithmetic number, because the mean of its divisors is an integer number (677126832529).

Almost surely, 21354253665057 is an apocalyptic number.

It is an amenable number.

1354253665057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354253665057 is an equidigital number, since it uses as much as digits as its factorization.

1354253665057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11340000, while the sum is 52.

The spelling of 1354253665057 in words is "one trillion, three hundred fifty-four billion, two hundred fifty-three million, six hundred sixty-five thousand, fifty-seven".