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1354253665081 is a prime number
BaseRepresentation
bin10011101101001111110…
…011110000001100111001
311210110120021012012101011
4103231033303300030321
5134142002414240311
62514045135553521
7166561445136142
oct23551763601471
94713507165334
101354253665081
11482376985829
1219a56898b8a1
139a9231b2545
1449790bc0ac9
1525361e4a321
hex13b4fcf0339

1354253665081 has 2 divisors, whose sum is σ = 1354253665082. Its totient is φ = 1354253665080.

The previous prime is 1354253665073. The next prime is 1354253665087. The reversal of 1354253665081 is 1805663524531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1350048791056 + 4204874025 = 1161916^2 + 64845^2 .

It is a cyclic number.

It is not a de Polignac number, because 1354253665081 - 23 = 1354253665073 is a prime.

It is a super-2 number, since 2×13542536650812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1354253665087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677126832540 + 677126832541.

It is an arithmetic number, because the mean of its divisors is an integer number (677126832541).

Almost surely, 21354253665081 is an apocalyptic number.

It is an amenable number.

1354253665081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354253665081 is an equidigital number, since it uses as much as digits as its factorization.

1354253665081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592000, while the sum is 49.

The spelling of 1354253665081 in words is "one trillion, three hundred fifty-four billion, two hundred fifty-three million, six hundred sixty-five thousand, eighty-one".