Base | Representation |
---|---|
bin | 1100010100010010010001… |
… | …0101110001100100100101 |
3 | 1202221122220222100112202102 |
4 | 3011010210111301210211 |
5 | 3233340312220302013 |
6 | 44445223104421445 |
7 | 2565265166016242 |
oct | 305044425614445 |
9 | 52848828315672 |
10 | 13542641572133 |
11 | 43514471254a3 |
12 | 16287a3317885 |
13 | 7730b122597b |
14 | 34b67859a5c9 |
15 | 18741db44d58 |
hex | c5124571925 |
13542641572133 has 4 divisors (see below), whose sum is σ = 13674123529248. Its totient is φ = 13411159615020.
The previous prime is 13542641572087. The next prime is 13542641572139. The reversal of 13542641572133 is 33127514624531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13542641572133 - 214 = 13542641555749 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13542641572139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65740978403 + ... + 65740978608.
It is an arithmetic number, because the mean of its divisors is an integer number (3418530882312).
Almost surely, 213542641572133 is an apocalyptic number.
It is an amenable number.
13542641572133 is a deficient number, since it is larger than the sum of its proper divisors (131481957115).
13542641572133 is a wasteful number, since it uses less digits than its factorization.
13542641572133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131481957114.
The product of its digits is 1814400, while the sum is 47.
The spelling of 13542641572133 in words is "thirteen trillion, five hundred forty-two billion, six hundred forty-one million, five hundred seventy-two thousand, one hundred thirty-three".
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