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1354324310531 is a prime number
BaseRepresentation
bin10011101101010100000…
…001001111101000000011
311210110202012010100201022
4103231110001033220003
5134142124010414111
62514100142100055
7166563263461433
oct23552401175003
94713665110638
101354324310531
114824028477a5
1219a58857a62b
139a934a18a9a
144979a3302c3
15253682522db
hex13b5404fa03

1354324310531 has 2 divisors, whose sum is σ = 1354324310532. Its totient is φ = 1354324310530.

The previous prime is 1354324310503. The next prime is 1354324310567. The reversal of 1354324310531 is 1350134234531.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354324310531 is a prime.

It is a super-2 number, since 2×13543243105312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1354324310491 and 1354324310500.

It is not a weakly prime, because it can be changed into another prime (1354324310831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677162155265 + 677162155266.

It is an arithmetic number, because the mean of its divisors is an integer number (677162155266).

Almost surely, 21354324310531 is an apocalyptic number.

1354324310531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354324310531 is an equidigital number, since it uses as much as digits as its factorization.

1354324310531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

The spelling of 1354324310531 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-four million, three hundred ten thousand, five hundred thirty-one".