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13544043203 is a prime number
BaseRepresentation
bin11001001110100100…
…11011001011000011
31021221220111200102202
430213102123023003
5210214233340303
610115543503415
7656430316265
oct144722331303
937856450382
1013544043203
115820294139
12275ba57b6b
13137b007a62
14926b07b35
155440b9c88
hex32749b2c3

13544043203 has 2 divisors, whose sum is σ = 13544043204. Its totient is φ = 13544043202.

The previous prime is 13544043179. The next prime is 13544043257. The reversal of 13544043203 is 30234044531.

13544043203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13544043203 - 210 = 13544042179 is a prime.

It is a super-2 number, since 2×135440432032 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (13544043263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6772021601 + 6772021602.

It is an arithmetic number, because the mean of its divisors is an integer number (6772021602).

Almost surely, 213544043203 is an apocalyptic number.

13544043203 is a deficient number, since it is larger than the sum of its proper divisors (1).

13544043203 is an equidigital number, since it uses as much as digits as its factorization.

13544043203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 13544043203 its reverse (30234044531), we get a palindrome (43778087734).

The spelling of 13544043203 in words is "thirteen billion, five hundred forty-four million, forty-three thousand, two hundred three".