Base | Representation |
---|---|
bin | 11110110010111010110101… |
… | …010101100000001011101011 |
3 | 122202112222201011210020110101 |
4 | 132302322311111200023223 |
5 | 120223024212000300003 |
6 | 1200020305305330231 |
7 | 40346153603330044 |
oct | 3662726525401353 |
9 | 582488634706411 |
10 | 135440541025003 |
11 | 3a179013532225 |
12 | 1323534b196977 |
13 | 5a75cb0157376 |
14 | 25635000a98cb |
15 | 109d1bc91911d |
hex | 7b2eb55602eb |
135440541025003 has 2 divisors, whose sum is σ = 135440541025004. Its totient is φ = 135440541025002.
The previous prime is 135440541024961. The next prime is 135440541025063. The reversal of 135440541025003 is 300520145044531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135440541025003 is a prime.
It is not a weakly prime, because it can be changed into another prime (135440541025063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67720270512501 + 67720270512502.
It is an arithmetic number, because the mean of its divisors is an integer number (67720270512502).
Almost surely, 2135440541025003 is an apocalyptic number.
135440541025003 is a deficient number, since it is larger than the sum of its proper divisors (1).
135440541025003 is an equidigital number, since it uses as much as digits as its factorization.
135440541025003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 135440541025003 its reverse (300520145044531), we get a palindrome (435960686069534).
The spelling of 135440541025003 in words is "one hundred thirty-five trillion, four hundred forty billion, five hundred forty-one million, twenty-five thousand, three".
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