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135441534000 = 24353374331409
BaseRepresentation
bin111111000100011110…
…0011100110000110000
3110221121011010210222010
41332020330130300300
54204341013042000
6142115422042520
712533240020653
oct1761074346060
9427534123863
10135441534000
1152493240173
12222bb119440
13ca06357836
1467ac06389a
1537ca934d50
hex1f88f1cc30

135441534000 has 320 divisors, whose sum is σ = 449819959680. Its totient is φ = 35035545600.

The previous prime is 135441533999. The next prime is 135441534043. The reversal of 135441534000 is 435144531.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 96125296 + ... + 96126704.

It is an arithmetic number, because the mean of its divisors is an integer number (1405687374).

Almost surely, 2135441534000 is an apocalyptic number.

135441534000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135441534000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (224909979840).

135441534000 is an abundant number, since it is smaller than the sum of its proper divisors (314378425680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135441534000 is a wasteful number, since it uses less digits than its factorization.

135441534000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1905 (or 1889 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 135441534000 its reverse (435144531), we get a palindrome (135876678531).

The spelling of 135441534000 in words is "one hundred thirty-five billion, four hundred forty-one million, five hundred thirty-four thousand".