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135442057 is a prime number
BaseRepresentation
bin10000001001010…
…10111010001001
3100102212011120111
420010222322021
5234133121212
621234554321
73233144542
oct1004527211
9312764514
10135442057
116a4a9693
12394389a1
13220a283a
1413db94c9
15bd55ea7
hex812ae89

135442057 has 2 divisors, whose sum is σ = 135442058. Its totient is φ = 135442056.

The previous prime is 135442033. The next prime is 135442061. The reversal of 135442057 is 750244531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135001161 + 440896 = 11619^2 + 664^2 .

It is a cyclic number.

It is not a de Polignac number, because 135442057 - 211 = 135440009 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (135442067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67721028 + 67721029.

It is an arithmetic number, because the mean of its divisors is an integer number (67721029).

Almost surely, 2135442057 is an apocalyptic number.

It is an amenable number.

135442057 is a deficient number, since it is larger than the sum of its proper divisors (1).

135442057 is an equidigital number, since it uses as much as digits as its factorization.

135442057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 31.

The square root of 135442057 is about 11637.9575957296. The cubic root of 135442057 is about 513.5521049388.

Adding to 135442057 its reverse (750244531), we get a palindrome (885686588).

It can be divided in two parts, 135 and 442057, that multiplied together give a palindrome (59677695).

The spelling of 135442057 in words is "one hundred thirty-five million, four hundred forty-two thousand, fifty-seven".