Base | Representation |
---|---|
bin | 111111000100011111… |
… | …1011101111110011011 |
3 | 110221121012122000120100 |
4 | 1332020333131332123 |
5 | 4204341213403103 |
6 | 142115451030443 |
7 | 12533246525160 |
oct | 1761077357633 |
9 | 427535560510 |
10 | 135442325403 |
11 | 52493730820 |
12 | 222bb43b423 |
13 | ca06573b18 |
14 | 67ac1cc067 |
15 | 37caa3e5a3 |
hex | 1f88fddf9b |
135442325403 has 48 divisors (see below), whose sum is σ = 249585912576. Its totient is φ = 68723363520.
The previous prime is 135442325357. The next prime is 135442325407. The reversal of 135442325403 is 304523244531.
135442325403 is a `hidden beast` number, since 13 + 5 + 4 + 4 + 232 + 5 + 403 = 666.
It is not a de Polignac number, because 135442325403 - 213 = 135442317211 is a prime.
It is a super-2 number, since 2×1354423254032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135442325407) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2242800 + ... + 2302397.
It is an arithmetic number, because the mean of its divisors is an integer number (5199706512).
Almost surely, 2135442325403 is an apocalyptic number.
135442325403 is a deficient number, since it is larger than the sum of its proper divisors (114143587173).
135442325403 is a wasteful number, since it uses less digits than its factorization.
135442325403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4545264 (or 4545261 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 36.
Adding to 135442325403 its reverse (304523244531), we get a palindrome (439965569934).
The spelling of 135442325403 in words is "one hundred thirty-five billion, four hundred forty-two million, three hundred twenty-five thousand, four hundred three".
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