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13544345005 = 53187382871
BaseRepresentation
bin11001001110100111…
…00100110110101101
31021221221002000102121
430213103210312231
5210214323020010
610115554152541
7656433014212
oct144723446655
937857060377
1013544345005
11582047a964
12275bb82751
13137b0b2239
14926b85b09
155441293da
hex3274e4dad

13544345005 has 8 divisors (see below), whose sum is σ = 16777511424. Its totient is φ = 10485944400.

The previous prime is 13544344969. The next prime is 13544345021. The reversal of 13544345005 is 50054344531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13544345005 - 211 = 13544342957 is a prime.

It is a super-2 number, since 2×135443450052 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43691281 + ... + 43691590.

It is an arithmetic number, because the mean of its divisors is an integer number (2097188928).

Almost surely, 213544345005 is an apocalyptic number.

It is an amenable number.

13544345005 is a deficient number, since it is larger than the sum of its proper divisors (3233166419).

13544345005 is an equidigital number, since it uses as much as digits as its factorization.

13544345005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87382907.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 13544345005 its reverse (50054344531), we get a palindrome (63598689536).

The spelling of 13544345005 in words is "thirteen billion, five hundred forty-four million, three hundred forty-five thousand, five".

Divisors: 1 5 31 155 87382871 436914355 2708869001 13544345005