Base | Representation |
---|---|
bin | 111111000100100010… |
… | …0000100001010100011 |
3 | 110221121021220020111222 |
4 | 1332021010010022203 |
5 | 4204342020433103 |
6 | 142115532525255 |
7 | 12533263004246 |
oct | 1761104041243 |
9 | 427537806458 |
10 | 135443530403 |
11 | 52494384095 |
12 | 222bb92082b |
13 | ca068a643c |
14 | 67ac42325d |
15 | 37cabcb638 |
hex | 1f891042a3 |
135443530403 has 2 divisors, whose sum is σ = 135443530404. Its totient is φ = 135443530402.
The previous prime is 135443530393. The next prime is 135443530441. The reversal of 135443530403 is 304035344531.
It is a weak prime.
It is an emirp because it is prime and its reverse (304035344531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135443530403 - 228 = 135175094947 is a prime.
It is not a weakly prime, because it can be changed into another prime (135443530303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67721765201 + 67721765202.
It is an arithmetic number, because the mean of its divisors is an integer number (67721765202).
Almost surely, 2135443530403 is an apocalyptic number.
135443530403 is a deficient number, since it is larger than the sum of its proper divisors (1).
135443530403 is an equidigital number, since it uses as much as digits as its factorization.
135443530403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 135443530403 its reverse (304035344531), we get a palindrome (439478874934).
The spelling of 135443530403 in words is "one hundred thirty-five billion, four hundred forty-three million, five hundred thirty thousand, four hundred three".
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