Base | Representation |
---|---|
bin | 1100010100011011001011… |
… | …0001100010100110001111 |
3 | 1202221220002111220000012102 |
4 | 3011012302301202212033 |
5 | 3233410210442344003 |
6 | 44450300151025315 |
7 | 2565411333446444 |
oct | 305066261424617 |
9 | 52856074800172 |
10 | 13545031215503 |
11 | 4352463003977 |
12 | 162914b66b23b |
13 | 7733a2326628 |
14 | 34b823ac19cb |
15 | 18750d822588 |
hex | c51b2c6298f |
13545031215503 has 4 divisors (see below), whose sum is σ = 13545449007888. Its totient is φ = 13544613423120.
The previous prime is 13545031215461. The next prime is 13545031215557. The reversal of 13545031215503 is 30551213054531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13545031215503 - 224 = 13545014438287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13545031215563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208847558 + ... + 208912403.
It is an arithmetic number, because the mean of its divisors is an integer number (3386362251972).
Almost surely, 213545031215503 is an apocalyptic number.
13545031215503 is a deficient number, since it is larger than the sum of its proper divisors (417792385).
13545031215503 is an equidigital number, since it uses as much as digits as its factorization.
13545031215503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 417792384.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 13545031215503 in words is "thirteen trillion, five hundred forty-five billion, thirty-one million, two hundred fifteen thousand, five hundred three".
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