Base | Representation |
---|---|
bin | 1100010100101110000110… |
… | …1100100111111010000001 |
3 | 1202222101012200221220012212 |
4 | 3011023201230213322001 |
5 | 3234001113014013402 |
6 | 44452500340231505 |
7 | 2565651304503035 |
oct | 305134154477201 |
9 | 52871180856185 |
10 | 13550113422977 |
11 | 435463085a63a |
12 | 162a12969b595 |
13 | 773a022092a1 |
14 | 34bb86a621c5 |
15 | 187709ab6952 |
hex | c52e1b27e81 |
13550113422977 has 2 divisors, whose sum is σ = 13550113422978. Its totient is φ = 13550113422976.
The previous prime is 13550113422953. The next prime is 13550113423043. The reversal of 13550113422977 is 77922431105531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12916268154241 + 633845268736 = 3593921^2 + 796144^2 .
It is a cyclic number.
It is not a de Polignac number, because 13550113422977 - 222 = 13550109228673 is a prime.
It is not a weakly prime, because it can be changed into another prime (13550113422077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775056711488 + 6775056711489.
It is an arithmetic number, because the mean of its divisors is an integer number (6775056711489).
Almost surely, 213550113422977 is an apocalyptic number.
It is an amenable number.
13550113422977 is a deficient number, since it is larger than the sum of its proper divisors (1).
13550113422977 is an equidigital number, since it uses as much as digits as its factorization.
13550113422977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1587600, while the sum is 50.
The spelling of 13550113422977 in words is "thirteen trillion, five hundred fifty billion, one hundred thirteen million, four hundred twenty-two thousand, nine hundred seventy-seven".
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