Base | Representation |
---|---|
bin | 11001001111010011… |
… | …11110000001010001 |
3 | 1021222100010020220001 |
4 | 30213221332001101 |
5 | 210222323341444 |
6 | 10120324050001 |
7 | 656533633504 |
oct | 144751760121 |
9 | 37870106801 |
10 | 13550215249 |
11 | 582381a2aa |
12 | 2761b33901 |
13 | 137c38915c |
14 | 92787313b |
15 | 5448d88d4 |
hex | 327a7e051 |
13550215249 has 2 divisors, whose sum is σ = 13550215250. Its totient is φ = 13550215248.
The previous prime is 13550215183. The next prime is 13550215307. The reversal of 13550215249 is 94251205531.
13550215249 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11983243024 + 1566972225 = 109468^2 + 39585^2 .
It is a cyclic number.
It is not a de Polignac number, because 13550215249 - 27 = 13550215121 is a prime.
It is not a weakly prime, because it can be changed into another prime (13550215849) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775107624 + 6775107625.
It is an arithmetic number, because the mean of its divisors is an integer number (6775107625).
Almost surely, 213550215249 is an apocalyptic number.
It is an amenable number.
13550215249 is a deficient number, since it is larger than the sum of its proper divisors (1).
13550215249 is an equidigital number, since it uses as much as digits as its factorization.
13550215249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 13550215249 in words is "thirteen billion, five hundred fifty million, two hundred fifteen thousand, two hundred forty-nine".
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