Search a number
-
+
13550347697 is a prime number
BaseRepresentation
bin11001001111010100…
…11110010110110001
31021222100100222120112
430213222132112301
5210222342111242
610120330551105
7656535024605
oct144752362661
937870328515
1013550347697
1158238aa867
122761b98495
13137c404523
149278a9505
15544912c82
hex327a9e5b1

13550347697 has 2 divisors, whose sum is σ = 13550347698. Its totient is φ = 13550347696.

The previous prime is 13550347579. The next prime is 13550347703. The reversal of 13550347697 is 79674305531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12709405696 + 840942001 = 112736^2 + 28999^2 .

It is a cyclic number.

It is not a de Polignac number, because 13550347697 - 28 = 13550347441 is a prime.

It is a super-3 number, since 3×135503476973 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13550347997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775173848 + 6775173849.

It is an arithmetic number, because the mean of its divisors is an integer number (6775173849).

Almost surely, 213550347697 is an apocalyptic number.

It is an amenable number.

13550347697 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550347697 is an equidigital number, since it uses as much as digits as its factorization.

13550347697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2381400, while the sum is 50.

The spelling of 13550347697 in words is "thirteen billion, five hundred fifty million, three hundred forty-seven thousand, six hundred ninety-seven".