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135505502110142 = 2661102500379811
BaseRepresentation
bin11110110011110111010101…
…010100011000000110111110
3122202210012101102112021121122
4132303313111110120012332
5120230110232020011032
61200110211315030542
740353643443413603
oct3663672524300676
9582705342467548
10135505502110142
113a1a3619357a4a
1213245a5a59b452
135a7c163669498
1425667037b06aa
15109ec20988012
hex7b3dd55181be

135505502110142 has 8 divisors (see below), whose sum is σ = 203565754306632. Its totient is φ = 67650250674600.

The previous prime is 135505502110007. The next prime is 135505502110159. The reversal of 135505502110142 is 241011205505531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1355055021101422 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51250188584 + ... + 51250191227.

It is an arithmetic number, because the mean of its divisors is an integer number (25445719288329).

Almost surely, 2135505502110142 is an apocalyptic number.

135505502110142 is a deficient number, since it is larger than the sum of its proper divisors (68060252196490).

135505502110142 is a wasteful number, since it uses less digits than its factorization.

135505502110142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102500380474.

The product of its (nonzero) digits is 30000, while the sum is 35.

Adding to 135505502110142 its reverse (241011205505531), we get a palindrome (376516707615673).

The spelling of 135505502110142 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, one hundred forty-two".

Divisors: 1 2 661 1322 102500379811 205000759622 67752751055071 135505502110142