Base | Representation |
---|---|
bin | 11110110011110111010101… |
… | …010100011000000111000011 |
3 | 122202210012101102112021121211 |
4 | 132303313111110120013003 |
5 | 120230110232020011042 |
6 | 1200110211315030551 |
7 | 40353643443413611 |
oct | 3663672524300703 |
9 | 582705342467554 |
10 | 135505502110147 |
11 | 3a1a3619357a54 |
12 | 13245a5a59b457 |
13 | 5a7c1636694a0 |
14 | 25667037b06b1 |
15 | 109ec20988017 |
hex | 7b3dd55181c3 |
135505502110147 has 32 divisors (see below), whose sum is σ = 153831818649600. Its totient is φ = 118327244452992.
The previous prime is 135505502110007. The next prime is 135505502110159. The reversal of 135505502110147 is 741011205505531.
It is a cyclic number.
It is not a de Polignac number, because 135505502110147 - 223 = 135505493721539 is a prime.
It is a super-2 number, since 2×1355055021101472 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135505502110177) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2954548338 + ... + 2954594200.
It is an arithmetic number, because the mean of its divisors is an integer number (4807244332800).
Almost surely, 2135505502110147 is an apocalyptic number.
135505502110147 is a deficient number, since it is larger than the sum of its proper divisors (18326316539453).
135505502110147 is a wasteful number, since it uses less digits than its factorization.
135505502110147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62947.
The product of its (nonzero) digits is 105000, while the sum is 40.
Adding to 135505502110147 its reverse (741011205505531), we get a palindrome (876516707615678).
The spelling of 135505502110147 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, one hundred forty-seven".
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