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135505502110169 is a prime number
BaseRepresentation
bin11110110011110111010101…
…010100011000000111011001
3122202210012101102112021122122
4132303313111110120013121
5120230110232020011134
61200110211315031025
740353643443413642
oct3663672524300731
9582705342467578
10135505502110169
113a1a3619357a74
1213245a5a59b475
135a7c1636694b9
1425667037b06c9
15109ec2098802e
hex7b3dd55181d9

135505502110169 has 2 divisors, whose sum is σ = 135505502110170. Its totient is φ = 135505502110168.

The previous prime is 135505502110159. The next prime is 135505502110177. The reversal of 135505502110169 is 961011205505531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127125895600144 + 8379606510025 = 11275012^2 + 2894755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135505502110169 is a prime.

It is a super-2 number, since 2×1355055021101692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (135505502110159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752751055084 + 67752751055085.

It is an arithmetic number, because the mean of its divisors is an integer number (67752751055085).

Almost surely, 2135505502110169 is an apocalyptic number.

It is an amenable number.

135505502110169 is a deficient number, since it is larger than the sum of its proper divisors (1).

135505502110169 is an equidigital number, since it uses as much as digits as its factorization.

135505502110169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 202500, while the sum is 44.

The spelling of 135505502110169 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, one hundred sixty-nine".