Base | Representation |
---|---|
bin | 11110110011110111010101… |
… | …010100011000001100100011 |
3 | 122202210012101102112022002212 |
4 | 132303313111110120030203 |
5 | 120230110232020013444 |
6 | 1200110211315032335 |
7 | 40353643443414623 |
oct | 3663672524301443 |
9 | 582705342468085 |
10 | 135505502110499 |
11 | 3a1a3619358244 |
12 | 13245a5a59b6ab |
13 | 5a7c1636696b1 |
14 | 25667037b0883 |
15 | 109ec2098819e |
hex | 7b3dd5518323 |
135505502110499 has 2 divisors, whose sum is σ = 135505502110500. Its totient is φ = 135505502110498.
The previous prime is 135505502110441. The next prime is 135505502110507. The reversal of 135505502110499 is 994011205505531.
It is a strong prime.
It is an emirp because it is prime and its reverse (994011205505531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135505502110499 - 28 = 135505502110243 is a prime.
It is a super-2 number, since 2×1355055021104992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135505502110799) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752751055249 + 67752751055250.
It is an arithmetic number, because the mean of its divisors is an integer number (67752751055250).
Almost surely, 2135505502110499 is an apocalyptic number.
135505502110499 is a deficient number, since it is larger than the sum of its proper divisors (1).
135505502110499 is an equidigital number, since it uses as much as digits as its factorization.
135505502110499 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1215000, while the sum is 50.
The spelling of 135505502110499 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred two million, one hundred ten thousand, four hundred ninety-nine".
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