Base | Representation |
---|---|
bin | 1100010100110001011101… |
… | …0101110010001101101011 |
3 | 1202222110112102102202012122 |
4 | 3011030113111302031223 |
5 | 3234004433412434142 |
6 | 44453125530101455 |
7 | 2566012513306652 |
oct | 305142725621553 |
9 | 52873472382178 |
10 | 13551013405547 |
11 | 4354a5287a892 |
12 | 162a33ab7a88b |
13 | 773b167c7a57 |
14 | 34bc303b6199 |
15 | 18775dadd1d2 |
hex | c531757236b |
13551013405547 has 2 divisors, whose sum is σ = 13551013405548. Its totient is φ = 13551013405546.
The previous prime is 13551013405453. The next prime is 13551013405561. The reversal of 13551013405547 is 74550431015531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13551013405547 - 220 = 13551012356971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13551013405498 and 13551013405507.
It is not a weakly prime, because it can be changed into another prime (13551013485547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775506702773 + 6775506702774.
It is an arithmetic number, because the mean of its divisors is an integer number (6775506702774).
Almost surely, 213551013405547 is an apocalyptic number.
13551013405547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13551013405547 is an equidigital number, since it uses as much as digits as its factorization.
13551013405547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 630000, while the sum is 44.
The spelling of 13551013405547 in words is "thirteen trillion, five hundred fifty-one billion, thirteen million, four hundred five thousand, five hundred forty-seven".
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