Base | Representation |
---|---|
bin | 11110110011111100101101… |
… | …110000010111000011111011 |
3 | 122202210202022011011120002011 |
4 | 132303330231300113003323 |
5 | 120230204100341330222 |
6 | 1200113004544350351 |
7 | 40354236602504014 |
oct | 3663745560270373 |
9 | 582722264146064 |
10 | 135511280808187 |
11 | 3a1a6014276359 |
12 | 13246bb19153b7 |
13 | 5a7c87493003b |
14 | 2566ad105400b |
15 | 109ee5ce59c77 |
hex | 7b3f2dc170fb |
135511280808187 has 2 divisors, whose sum is σ = 135511280808188. Its totient is φ = 135511280808186.
The previous prime is 135511280808121. The next prime is 135511280808259. The reversal of 135511280808187 is 781808082115531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135511280808187 - 215 = 135511280775419 is a prime.
It is not a weakly prime, because it can be changed into another prime (135511280808487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67755640404093 + 67755640404094.
It is an arithmetic number, because the mean of its divisors is an integer number (67755640404094).
Almost surely, 2135511280808187 is an apocalyptic number.
135511280808187 is a deficient number, since it is larger than the sum of its proper divisors (1).
135511280808187 is an equidigital number, since it uses as much as digits as its factorization.
135511280808187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4300800, while the sum is 58.
The spelling of 135511280808187 in words is "one hundred thirty-five trillion, five hundred eleven billion, two hundred eighty million, eight hundred eight thousand, one hundred eighty-seven".
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