Base | Representation |
---|---|
bin | 11110110011111100101111… |
… | …101000111011000101010110 |
3 | 122202210202101100122020202022 |
4 | 132303330233220323011112 |
5 | 120230204131434204024 |
6 | 1200113012034013142 |
7 | 40354240435235246 |
oct | 3663745750730526 |
9 | 582722340566668 |
10 | 135511312413014 |
11 | 3a1a60300a254a |
12 | 132470004171b2 |
13 | 5a7c87b347615 |
14 | 2566ad531db26 |
15 | 109ee60aee35e |
hex | 7b3f2fa3b156 |
135511312413014 has 8 divisors (see below), whose sum is σ = 203773868791848. Its totient is φ = 67586689482400.
The previous prime is 135511312412981. The next prime is 135511312413017. The reversal of 135511312413014 is 410314213115531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135511312413017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84483361052 + ... + 84483362655.
It is an arithmetic number, because the mean of its divisors is an integer number (25471733598981).
Almost surely, 2135511312413014 is an apocalyptic number.
135511312413014 is a deficient number, since it is larger than the sum of its proper divisors (68262556378834).
135511312413014 is a wasteful number, since it uses less digits than its factorization.
135511312413014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 168966724110.
The product of its (nonzero) digits is 21600, while the sum is 35.
Adding to 135511312413014 its reverse (410314213115531), we get a palindrome (545825525528545).
The spelling of 135511312413014 in words is "one hundred thirty-five trillion, five hundred eleven billion, three hundred twelve million, four hundred thirteen thousand, fourteen".
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