Base | Representation |
---|---|
bin | 11110110011111101101101… |
… | …100000010011100001100111 |
3 | 122202210212001200200110120211 |
4 | 132303331231200103201213 |
5 | 120230213243141404343 |
6 | 1200113303032240251 |
7 | 40354305240415102 |
oct | 3663755540234147 |
9 | 582725050613524 |
10 | 135512350341223 |
11 | 3a1a6512a71359 |
12 | 1324724bb40087 |
13 | 5a7c9b53a431b |
14 | 2566b93101739 |
15 | 109eec1cc379d |
hex | 7b3f6d813867 |
135512350341223 has 16 divisors (see below), whose sum is σ = 138687761493216. Its totient is φ = 132359936716800.
The previous prime is 135512350341217. The next prime is 135512350341233. The reversal of 135512350341223 is 322143053215531.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135512350341223 is a prime.
It is a super-2 number, since 2×1355123503412232 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135512350341233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 163605523 + ... + 164431723.
It is an arithmetic number, because the mean of its divisors is an integer number (8667985093326).
Almost surely, 2135512350341223 is an apocalyptic number.
135512350341223 is a deficient number, since it is larger than the sum of its proper divisors (3175411151993).
135512350341223 is a wasteful number, since it uses less digits than its factorization.
135512350341223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 840114.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 135512350341223 in words is "one hundred thirty-five trillion, five hundred twelve billion, three hundred fifty million, three hundred forty-one thousand, two hundred twenty-three".
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