Base | Representation |
---|---|
bin | 11110110011111101110001… |
… | …101111011010011001100011 |
3 | 122202210212020122102011011200 |
4 | 132303331301233122121203 |
5 | 120230213414340113103 |
6 | 1200113314051412243 |
7 | 40354310062453632 |
oct | 3663756157323143 |
9 | 582725218364150 |
10 | 135512421410403 |
11 | 3a1a654a0a2714 |
12 | 1324726b8b4083 |
13 | 5a7c9c70286ab |
14 | 2566b9c721519 |
15 | 109eec81610a3 |
hex | 7b3f71bda663 |
135512421410403 has 24 divisors (see below), whose sum is σ = 195883966701696. Its totient is φ = 90275263084800.
The previous prime is 135512421410393. The next prime is 135512421410417. The reversal of 135512421410403 is 304014124215531.
135512421410403 is a `hidden beast` number, since 1 + 3 + 5 + 5 + 1 + 24 + 214 + 10 + 403 = 666.
It is not a de Polignac number, because 135512421410403 - 28 = 135512421410147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (135512421415403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 84406923 + ... + 85997403.
It is an arithmetic number, because the mean of its divisors is an integer number (8161831945904).
Almost surely, 2135512421410403 is an apocalyptic number.
135512421410403 is a deficient number, since it is larger than the sum of its proper divisors (60371545291293).
135512421410403 is a wasteful number, since it uses less digits than its factorization.
135512421410403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1597435 (or 1597432 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 135512421410403 its reverse (304014124215531), we get a palindrome (439526545625934).
The spelling of 135512421410403 in words is "one hundred thirty-five trillion, five hundred twelve billion, four hundred twenty-one million, four hundred ten thousand, four hundred three".
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