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13551342131 is a prime number
BaseRepresentation
bin11001001111011100…
…10001001000110011
31021222102020111200102
430213232101020303
5210223120422011
610120404143015
7656546336045
oct144756211063
937872214612
1013551342131
115824419a08
122762397a6b
13137c692052
14927a87a95
15544a5c73b
hex327b91233

13551342131 has 2 divisors, whose sum is σ = 13551342132. Its totient is φ = 13551342130.

The previous prime is 13551342121. The next prime is 13551342143. The reversal of 13551342131 is 13124315531.

13551342131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13551342131 - 26 = 13551342067 is a prime.

It is a super-2 number, since 2×135513421312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13551342094 and 13551342103.

It is not a weakly prime, because it can be changed into another prime (13551342121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775671065 + 6775671066.

It is an arithmetic number, because the mean of its divisors is an integer number (6775671066).

Almost surely, 213551342131 is an apocalyptic number.

13551342131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13551342131 is an equidigital number, since it uses as much as digits as its factorization.

13551342131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 29.

Adding to 13551342131 its reverse (13124315531), we get a palindrome (26675657662).

The spelling of 13551342131 in words is "thirteen billion, five hundred fifty-one million, three hundred forty-two thousand, one hundred thirty-one".