Base | Representation |
---|---|
bin | 10011101110000101001… |
… | …111001101110100101011 |
3 | 11210112212201220121120111 |
4 | 103232011033031310223 |
5 | 134200321403303442 |
6 | 2514314120435151 |
7 | 166622611266004 |
oct | 23560517156453 |
9 | 4715781817514 |
10 | 1355150056747 |
11 | 482796973093 |
12 | 19a779018ab7 |
13 | 9aa36b14706 |
14 | 49837c7c1ab |
15 | 253b59b2b17 |
hex | 13b853cdd2b |
1355150056747 has 2 divisors, whose sum is σ = 1355150056748. Its totient is φ = 1355150056746.
The previous prime is 1355150056717. The next prime is 1355150056811. The reversal of 1355150056747 is 7476500515531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1355150056747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1355150056747.
It is not a weakly prime, because it can be changed into another prime (1355150056717) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677575028373 + 677575028374.
It is an arithmetic number, because the mean of its divisors is an integer number (677575028374).
Almost surely, 21355150056747 is an apocalyptic number.
1355150056747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355150056747 is an equidigital number, since it uses as much as digits as its factorization.
1355150056747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2205000, while the sum is 49.
The spelling of 1355150056747 in words is "one trillion, three hundred fifty-five billion, one hundred fifty million, fifty-six thousand, seven hundred forty-seven".
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