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1355235052441 is a prime number
BaseRepresentation
bin10011101110001010010…
…011011100101110011001
311210120002122211211202011
4103232022103130232121
5134201010133134231
62514330354305521
7166624662606604
oct23561223345631
94716078754664
101355235052441
1148282a946666
1219a7a15882a1
139aa4b60391a
144984528533b
15253bd1a19b1
hex13b8a4dcb99

1355235052441 has 2 divisors, whose sum is σ = 1355235052442. Its totient is φ = 1355235052440.

The previous prime is 1355235052421. The next prime is 1355235052447. The reversal of 1355235052441 is 1442505325531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 820874052441 + 534361000000 = 906021^2 + 731000^2 .

It is a cyclic number.

It is not a de Polignac number, because 1355235052441 - 231 = 1353087568793 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1355235052394 and 1355235052403.

It is not a weakly prime, because it can be changed into another prime (1355235052447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677617526220 + 677617526221.

It is an arithmetic number, because the mean of its divisors is an integer number (677617526221).

Almost surely, 21355235052441 is an apocalyptic number.

It is an amenable number.

1355235052441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355235052441 is an equidigital number, since it uses as much as digits as its factorization.

1355235052441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 40.

The spelling of 1355235052441 in words is "one trillion, three hundred fifty-five billion, two hundred thirty-five million, fifty-two thousand, four hundred forty-one".