Base | Representation |
---|---|
bin | 111111000110111011… |
… | …1001000000000100011 |
3 | 110221210220100202110110 |
4 | 1332031313020000203 |
5 | 4210023122234410 |
6 | 142131530102403 |
7 | 12535261125426 |
oct | 1761567100043 |
9 | 427726322413 |
10 | 135524024355 |
11 | 52525862415 |
12 | 2232287aa03 |
13 | ca1a47a5b5 |
14 | 67b8db79bd |
15 | 37d2ccb720 |
hex | 1f8ddc8023 |
135524024355 has 32 divisors (see below), whose sum is σ = 226545661440. Its totient is φ = 69051502080.
The previous prime is 135524024333. The next prime is 135524024423. The reversal of 135524024355 is 553420425531.
It is not a de Polignac number, because 135524024355 - 26 = 135524024291 is a prime.
It is a super-2 number, since 2×1355240243552 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37611 + ... + 521979.
It is an arithmetic number, because the mean of its divisors is an integer number (7079551920).
Almost surely, 2135524024355 is an apocalyptic number.
135524024355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
135524024355 is a deficient number, since it is larger than the sum of its proper divisors (91021637085).
135524024355 is a wasteful number, since it uses less digits than its factorization.
135524024355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 485211.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 135524024355 its reverse (553420425531), we get a palindrome (688944449886).
The spelling of 135524024355 in words is "one hundred thirty-five billion, five hundred twenty-four million, twenty-four thousand, three hundred fifty-five".
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