Base | Representation |
---|---|
bin | 10011101110001011010… |
… | …100001100101010110001 |
3 | 11210120010211210012010201 |
4 | 103232023110030222301 |
5 | 134201024004313113 |
6 | 2514332202155201 |
7 | 166625260102363 |
oct | 23561324145261 |
9 | 4716124705121 |
10 | 1355252026033 |
11 | 48283948a124 |
12 | 19a7a71b2b01 |
13 | 9aa51c97679 |
14 | 49847622d33 |
15 | 253be905cdd |
hex | 13b8b50cab1 |
1355252026033 has 2 divisors, whose sum is σ = 1355252026034. Its totient is φ = 1355252026032.
The previous prime is 1355252026001. The next prime is 1355252026067. The reversal of 1355252026033 is 3306202525531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 687055316544 + 668196709489 = 828888^2 + 817433^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355252026033 - 25 = 1355252026001 is a prime.
It is a super-3 number, since 3×13552520260333 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1355252025983 and 1355252026001.
It is not a weakly prime, because it can be changed into another prime (1355252023033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677626013016 + 677626013017.
It is an arithmetic number, because the mean of its divisors is an integer number (677626013017).
Almost surely, 21355252026033 is an apocalyptic number.
It is an amenable number.
1355252026033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355252026033 is an equidigital number, since it uses as much as digits as its factorization.
1355252026033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 37.
The spelling of 1355252026033 in words is "one trillion, three hundred fifty-five billion, two hundred fifty-two million, twenty-six thousand, thirty-three".
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