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1355253113651 is a prime number
BaseRepresentation
bin10011101110001011011…
…000010110001100110011
311210120010220211110001212
4103232023120112030303
5134201024244114101
62514332241350335
7166625302252313
oct23561330261463
94716126743055
101355253113651
1148283a062288
1219a7a76383ab
139aa52288728
1449847827443
15253bea6d1bb
hex13b8b616333

1355253113651 has 2 divisors, whose sum is σ = 1355253113652. Its totient is φ = 1355253113650.

The previous prime is 1355253113611. The next prime is 1355253113659. The reversal of 1355253113651 is 1563113525531.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1355253113651 is a prime.

It is a super-2 number, since 2×13552531136512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1355253113599 and 1355253113608.

It is not a weakly prime, because it can be changed into another prime (1355253113659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677626556825 + 677626556826.

It is an arithmetic number, because the mean of its divisors is an integer number (677626556826).

Almost surely, 21355253113651 is an apocalyptic number.

1355253113651 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355253113651 is an equidigital number, since it uses as much as digits as its factorization.

1355253113651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 202500, while the sum is 41.

The spelling of 1355253113651 in words is "one trillion, three hundred fifty-five billion, two hundred fifty-three million, one hundred thirteen thousand, six hundred fifty-one".