Base | Representation |
---|---|
bin | 10011101110001011011… |
… | …000010110001100110011 |
3 | 11210120010220211110001212 |
4 | 103232023120112030303 |
5 | 134201024244114101 |
6 | 2514332241350335 |
7 | 166625302252313 |
oct | 23561330261463 |
9 | 4716126743055 |
10 | 1355253113651 |
11 | 48283a062288 |
12 | 19a7a76383ab |
13 | 9aa52288728 |
14 | 49847827443 |
15 | 253bea6d1bb |
hex | 13b8b616333 |
1355253113651 has 2 divisors, whose sum is σ = 1355253113652. Its totient is φ = 1355253113650.
The previous prime is 1355253113611. The next prime is 1355253113659. The reversal of 1355253113651 is 1563113525531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1355253113651 is a prime.
It is a super-2 number, since 2×13552531136512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1355253113599 and 1355253113608.
It is not a weakly prime, because it can be changed into another prime (1355253113659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677626556825 + 677626556826.
It is an arithmetic number, because the mean of its divisors is an integer number (677626556826).
Almost surely, 21355253113651 is an apocalyptic number.
1355253113651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355253113651 is an equidigital number, since it uses as much as digits as its factorization.
1355253113651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 202500, while the sum is 41.
The spelling of 1355253113651 in words is "one trillion, three hundred fifty-five billion, two hundred fifty-three million, one hundred thirteen thousand, six hundred fifty-one".
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