Base | Representation |
---|---|
bin | 111111000111000011… |
… | …0111000000000100001 |
3 | 110221211012010112001201 |
4 | 1332032012320000201 |
5 | 4210030201344441 |
6 | 142132154401201 |
7 | 12535341202564 |
oct | 1761606700041 |
9 | 427735115051 |
10 | 135528153121 |
11 | 52528122419 |
12 | 22324130201 |
13 | ca1b29495a |
14 | 67b97704db |
15 | 37d3344c31 |
hex | 1f8e1b8021 |
135528153121 has 2 divisors, whose sum is σ = 135528153122. Its totient is φ = 135528153120.
The previous prime is 135528153077. The next prime is 135528153143. The reversal of 135528153121 is 121351825531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89114190400 + 46413962721 = 298520^2 + 215439^2 .
It is a cyclic number.
It is not a de Polignac number, because 135528153121 - 215 = 135528120353 is a prime.
It is not a weakly prime, because it can be changed into another prime (135528153161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67764076560 + 67764076561.
It is an arithmetic number, because the mean of its divisors is an integer number (67764076561).
Almost surely, 2135528153121 is an apocalyptic number.
It is an amenable number.
135528153121 is a deficient number, since it is larger than the sum of its proper divisors (1).
135528153121 is an equidigital number, since it uses as much as digits as its factorization.
135528153121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36000, while the sum is 37.
Adding to 135528153121 its reverse (121351825531), we get a palindrome (256879978652).
The spelling of 135528153121 in words is "one hundred thirty-five billion, five hundred twenty-eight million, one hundred fifty-three thousand, one hundred twenty-one".
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