Base | Representation |
---|---|
bin | 111111000111001101… |
… | …1010001011000110011 |
3 | 110221211120012011112121 |
4 | 1332032123101120303 |
5 | 4210033033444310 |
6 | 142132505135111 |
7 | 12535434512200 |
oct | 1761633213063 |
9 | 427746164477 |
10 | 135533499955 |
11 | 52530144597 |
12 | 22325a8a497 |
13 | ca1c417569 |
14 | 67ba362ca7 |
15 | 37d3a4e0da |
hex | 1f8e6d1633 |
135533499955 has 48 divisors (see below), whose sum is σ = 192581513280. Its totient is φ = 91277625600.
The previous prime is 135533499949. The next prime is 135533499967. The reversal of 135533499955 is 559994335531.
It is not a de Polignac number, because 135533499955 - 23 = 135533499947 is a prime.
It is a super-2 number, since 2×1355334999552 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (61).
It is a junction number, because it is equal to n+sod(n) for n = 135533499893 and 135533499902.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10589610 + ... + 10602400.
It is an arithmetic number, because the mean of its divisors is an integer number (4012114860).
Almost surely, 2135533499955 is an apocalyptic number.
135533499955 is a deficient number, since it is larger than the sum of its proper divisors (57048013325).
135533499955 is a wasteful number, since it uses less digits than its factorization.
135533499955 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13580 (or 13573 counting only the distinct ones).
The product of its digits is 49207500, while the sum is 61.
The spelling of 135533499955 in words is "one hundred thirty-five billion, five hundred thirty-three million, four hundred ninety-nine thousand, nine hundred fifty-five".
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