Base | Representation |
---|---|
bin | 11110110100010010001010… |
… | …000111001110000111011100 |
3 | 122202212221201202111212022011 |
4 | 132310102022013032013130 |
5 | 120231043224104004322 |
6 | 1200131333352001004 |
7 | 40356013300220245 |
oct | 3664221207160734 |
9 | 582787652455264 |
10 | 135534305141212 |
11 | 3a20485997555a |
12 | 1324b558690164 |
13 | 5a81aa3a5b933 |
14 | 2567c76c77ccc |
15 | 10a0859474677 |
hex | 7b448a1ce1dc |
135534305141212 has 12 divisors (see below), whose sum is σ = 237269712715056. Its totient is φ = 67742958651200.
The previous prime is 135534305141173. The next prime is 135534305141233. The reversal of 135534305141212 is 212141503435531.
It is a super-2 number, since 2×1355343051412122 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6048467248 + ... + 6048489655.
It is an arithmetic number, because the mean of its divisors is an integer number (19772476059588).
Almost surely, 2135534305141212 is an apocalyptic number.
It is an amenable number.
135534305141212 is a deficient number, since it is larger than the sum of its proper divisors (101735407573844).
135534305141212 is a wasteful number, since it uses less digits than its factorization.
135534305141212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12096959708 (or 12096959706 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 40.
Adding to 135534305141212 its reverse (212141503435531), we get a palindrome (347675808576743).
The spelling of 135534305141212 in words is "one hundred thirty-five trillion, five hundred thirty-four billion, three hundred five million, one hundred forty-one thousand, two hundred twelve".
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