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135534314351 = 343639394409
BaseRepresentation
bin111111000111001111…
…0011000001101101111
3110221211121201112200102
41332032132120031233
54210033241024401
6142132534421315
712535444443422
oct1761636301557
9427747645612
10135534314351
1152530650447
122232620183b
13ca1c641157
1467ba4d59b9
1537d3b6056b
hex1f8e79836f

135534314351 has 4 divisors (see below), whose sum is σ = 135535052400. Its totient is φ = 135533576304.

The previous prime is 135534314317. The next prime is 135534314353. The reversal of 135534314351 is 153413435531.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135534314351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135534314353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146435 + ... + 540843.

It is an arithmetic number, because the mean of its divisors is an integer number (33883763100).

Almost surely, 2135534314351 is an apocalyptic number.

135534314351 is a deficient number, since it is larger than the sum of its proper divisors (738049).

135534314351 is an equidigital number, since it uses as much as digits as its factorization.

135534314351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 738048.

The product of its digits is 162000, while the sum is 38.

Adding to 135534314351 its reverse (153413435531), we get a palindrome (288947749882).

The spelling of 135534314351 in words is "one hundred thirty-five billion, five hundred thirty-four million, three hundred fourteen thousand, three hundred fifty-one".

Divisors: 1 343639 394409 135534314351