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135535305352147 is a prime number
BaseRepresentation
bin11110110100010011000101…
…101110101110001111010011
3122202220001022110120211202121
4132310103011232232033103
5120231102301132232042
61200132020521555111
740356050133660151
oct3664230556561723
9582801273524677
10135535305352147
113a205222522868
121324b797645a97
135a81c03040b1c
142567d2da3c3d1
1510a08b7198367
hex7b44c5bae3d3

135535305352147 has 2 divisors, whose sum is σ = 135535305352148. Its totient is φ = 135535305352146.

The previous prime is 135535305352099. The next prime is 135535305352163. The reversal of 135535305352147 is 741253503535531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135535305352147 - 219 = 135535304827859 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135535305352094 and 135535305352103.

It is not a weakly prime, because it can be changed into another prime (135535305362147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767652676073 + 67767652676074.

It is an arithmetic number, because the mean of its divisors is an integer number (67767652676074).

Almost surely, 2135535305352147 is an apocalyptic number.

135535305352147 is a deficient number, since it is larger than the sum of its proper divisors (1).

135535305352147 is an equidigital number, since it uses as much as digits as its factorization.

135535305352147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14175000, while the sum is 52.

Adding to 135535305352147 its reverse (741253503535531), we get a palindrome (876788808887678).

The spelling of 135535305352147 in words is "one hundred thirty-five trillion, five hundred thirty-five billion, three hundred five million, three hundred fifty-two thousand, one hundred forty-seven".