Base | Representation |
---|---|
bin | 101000011001001… |
… | …1100100001001011 |
3 | 10111110102112000211 |
4 | 1100302130201023 |
5 | 10233440320131 |
6 | 342254541551 |
7 | 45405502156 |
oct | 12062344113 |
9 | 3443375024 |
10 | 1355401291 |
11 | 6360a8062 |
12 | 319b078b7 |
13 | 187a649ca |
14 | cc022c9d |
15 | 7ded55b1 |
hex | 50c9c84b |
1355401291 has 2 divisors, whose sum is σ = 1355401292. Its totient is φ = 1355401290.
The previous prime is 1355401283. The next prime is 1355401331. The reversal of 1355401291 is 1921045531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1355401291 - 23 = 1355401283 is a prime.
It is a super-2 number, since 2×13554012912 = 3674225319288933362, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1355401241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677700645 + 677700646.
It is an arithmetic number, because the mean of its divisors is an integer number (677700646).
Almost surely, 21355401291 is an apocalyptic number.
1355401291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355401291 is an equidigital number, since it uses as much as digits as its factorization.
1355401291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 31.
The square root of 1355401291 is about 36815.7750291910. The cubic root of 1355401291 is about 1106.6814530955.
The spelling of 1355401291 in words is "one billion, three hundred fifty-five million, four hundred one thousand, two hundred ninety-one".
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