Base | Representation |
---|---|
bin | 10011101110010100110… |
… | …011000100001011111001 |
3 | 11210120112221010122000101 |
4 | 103232110303010023321 |
5 | 134201340221101242 |
6 | 2514400044035401 |
7 | 166632231236035 |
oct | 23562463041371 |
9 | 4716487118011 |
10 | 1355411112697 |
11 | 482910268304 |
12 | 19a830532b61 |
13 | 9aa78c284a5 |
14 | 498607d51c5 |
15 | 253cd87c9b7 |
hex | 13b94cc42f9 |
1355411112697 has 2 divisors, whose sum is σ = 1355411112698. Its totient is φ = 1355411112696.
The previous prime is 1355411112623. The next prime is 1355411112709. The reversal of 1355411112697 is 7962111145531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 714356278416 + 641054834281 = 845196^2 + 800659^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355411112697 - 211 = 1355411110649 is a prime.
It is a super-2 number, since 2×13554111126972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1355411118697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677705556348 + 677705556349.
It is an arithmetic number, because the mean of its divisors is an integer number (677705556349).
Almost surely, 21355411112697 is an apocalyptic number.
It is an amenable number.
1355411112697 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355411112697 is an equidigital number, since it uses as much as digits as its factorization.
1355411112697 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 226800, while the sum is 46.
The spelling of 1355411112697 in words is "one trillion, three hundred fifty-five billion, four hundred eleven million, one hundred twelve thousand, six hundred ninety-seven".
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