135543441113143 has 4 divisors (see below), whose sum is σ = 154906789843600. Its totient is φ = 116180092382688.

The previous prime is 135543441113141. The next prime is 135543441113161. The reversal of 135543441113143 is 341311144345531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135543441113143 - 2¹ = 135543441113141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135543441113143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135543441113141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9681674365218 + ... + 9681674365231.

It is an arithmetic number, because the mean of its divisors is an integer number (38726697460900).

Almost surely, 2^{135543441113143} is an apocalyptic number.

135543441113143 is a deficient number, since it is larger than the sum of its proper divisors (19363348730457).

135543441113143 is an equidigital number, since it uses as much as digits as its factorization.

135543441113143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19363348730456.

The product of its digits is 518400, while the sum is 43.

Adding to 135543441113143 its reverse (341311144345531), we get a palindrome (476854585458674).

The spelling of 135543441113143 in words is "one hundred thirty-five trillion, five hundred forty-three billion, four hundred forty-one million, one hundred thirteen thousand, one hundred forty-three".